Log in 😊 8 years agoPosted 8 years ago. Direct link to 😊's post “What if you have a fracti...” What if you have a fraction in the equation that's like : 7/x-9 and the other side of the equation has -2/x, how would you work that out? • (20 votes) Ms. Brohi 4 years agoPosted 4 years ago. Direct link to Ms. Brohi's post “You will cross multiply a...” You will cross multiply and then solve. To cross multiply, multiply the denominator on the left by the numerator on the right. Then do the same for the denominator on the right and the numerator on the left. These new expressions will be equal to each other. For your example, it will look like: (x-9)(-2)=(x)(7) (20 votes) Evgeniy Fateev 3 years agoPosted 3 years ago. Direct link to Evgeniy Fateev's post “What about this equation?...” What about this equation? We can try to solve it as usual: Then isolate x (subtract it from the both sides) This is equals Subtract 6 from the both sides Divide by 2 both sides But we can't substitute zero instead of So should we care about exclusions for • (12 votes) Kim Seidel 3 years agoPosted 3 years ago. Direct link to Kim Seidel's post “Yes, you should care abou...” Yes, you should care about exclusions for X. While your work created x=0, it is not a valid solution because it doesn't make the equation be true (both sides equal). Division by 0 is undefined. (11 votes) bguadarrama 7 years agoPosted 7 years ago. Direct link to bguadarrama's post “If 19=43+X what is the va...” If 19=43+X what is the value of X • (4 votes) Dominic Nguyen 7 years agoPosted 7 years ago. Direct link to Dominic Nguyen's post “The answer is negative 24...” The answer is negative 24, because 43+(-24)=19, or you can solve it by isolating the x, to do this, put the-equation X+43=19, subtract 43 from both sides so it will look like, (X+43)-43=(19)-43, so (x+43)-43 is X, (19)-43 is -24, so X=-24. Hope this helps. (23 votes) Bosco a year agoPosted a year ago. Direct link to Bosco's post “I got the right answer to...” I got the right answer too when I added 10/x both sides of the equation. • (15 votes) Khanfusing 5 months agoPosted 5 months ago. Direct link to Khanfusing's post “Nice! Now you gotta do th...” Nice! Now you gotta do that multiple times... (0 votes) Çħárłés 4 years agoPosted 4 years ago. Direct link to Çħárłés's post “if you keep pushing 1 on ...” if you keep pushing 1 on ur keyboard he says boat boat boat boat • (12 votes) Tony Wu 5 years agoPosted 5 years ago. Direct link to Tony Wu's post “In the video, Sal minused...” In the video, Sal minused the 2x, but couldn't you also minus the 7x to? I • (2 votes) Kim Seidel 5 years agoPosted 5 years ago. Direct link to Kim Seidel's post “Yes, you could have subtr...” Yes, you could have subtracted 7x rather than the 2x. If you prefer to work with positive numbers, then moving the 2x keeps the coefficient of x a positive value. (21 votes) Valentin Gao a year agoPosted a year ago. Direct link to Valentin Gao's post “What if the numerator on ...” What if the numerator on both sides is x and the denominator of both fractions does not have a common multiple? Could we still solve for x using this method or some other type? • (6 votes) VIBB a year agoPosted a year ago. Direct link to VIBB's post “IDKask chat gpt” IDK (11 votes) Alyssa Holt 6 years agoPosted 6 years ago. Direct link to Alyssa Holt's post “so all we really have to ...” so all we really have to do is distribute the x and then go from there? • (7 votes) Jazlynn de Guzman 10 years agoPosted 10 years ago. Direct link to Jazlynn de Guzman's post “Why does multiplying x by...” Why does multiplying x by 10/x get you 10? Is it because if u multiply you get 10x over x which simplifies into 10? • (4 votes) txjclanike 10 years agoPosted 10 years ago. Direct link to txjclanike's post “Remember that "x" is real...” Remember that "x" is really "x/1," just like 2 is 2/1. Now look back at your original problem, x • 10/x. When you multiply (remember that x = x/1), you end up with 10x/x. Now we need to simplify. Obviously the only factor between the top and bottom is x, so we divide both the numerator and the denominator by x. (4 votes) Genny 3 years agoPosted 3 years ago. Direct link to Genny's post “What is 7Xsomething is7” What is 7Xsomething is7 • (3 votes) Delta Whiskey 3 years agoPosted 3 years ago. Direct link to Delta Whiskey's post “Do you mean 7 * x = 7, if...” Do you mean 7 * x = 7, if so, then x = 1 (5 votes)Want to join the conversation?
Distribute/multiply to get:
-2x + 18 = 7x
Add 2x to both sides to gather your variables:
18 = 9x
Divide both sides by 9.
2 = x6/x + 3 = 12/2x + 1Let's multiply both sides on x
6 + 3x = 12/2 + x
6 + 2x = 12/2
6 + 2x = 6
2x = 0
x = 0x in the equation because it's impossible to have zero as denominator.x when it resides in denominator?
7-10/x=2+15/x
7+10/x-10/x=2+10/x+15/x
7=2+25/x
-2+7=-2+2+25/x
5=25/x
5=x
ask chat gpt
Let's take a similar problem without variables: 2 • 3/2.
When you multiply 2 (or 2/1) by 3/2, you multiply numerator by numerator, and denominator by denominator. You end up with 6/2. When you reduce (or simplify), you divide both the numerator and the denominator by their GCF (greatest common factor). 6/2 = 3, and 2/2 = 1.
So you're left with 3/1, or 3.
10x/x = 10, and x/x = 1,
so we're left with 10/1, or 10.
Video transcript
So I have the equation 7 minus10/x is equal to 2 plus 15/x. And so this isn'tthe type of equation that you might think thatyou're used to solving. But I'll give you afew moments to see if you can solve it on your own. Well, what we'll see is wecan do a quick multiplication of both sides to actuallysimplify this to a form that we are moreused to looking at. So what's probably botheringyou, because it's bothering me, is these x's that we have in thedenominators right over here. We're like, well, howdo we deal with that? Well, whenever we seean x in the denominator, the temptation isto multiply it by x. But we can't just multiplyone of the terms by x. We have to multiplythe entire side by x. So we could multiplythis entire side by x. But we can't just multiplythe left-hand side by x. We'd also want to multiplythe right-hand side by x. And so what will that give us? Well, we distribute the x. We get x times 7 is 7x. And then x timesnegative 10/x, well, that's just goingto be negative 10. So you get negative10 right over there. So the left-hand sidesimplifies to 7x minus 10. And then your right-handside, once again, distribute the x.x times 2 is 2x. x times 15/x, well,x times something over x is just going to bethe something. x times 15/x is just going tobe 15-- plus 15. So now we've simplifiedthis to a linear equation. We have the variableon both sides. So we just have to dosome of the techniques that we already know. So the first thingthat I like to do is maybe get all my x'son the left-hand side. So I want to get rid ofthis 2x right over here. So I subtract 2x fromthe right-hand side. Now, and I always remindyou, I can't do that just to the right-hand side. If I did it just tothe right-hand side, it wouldn't be anequality anymore. You have to do that to theleft-hand side as well. And so we are left with-- letme get that pink color again. On the left-hand side, 7x, 7 ofsomething minus 2 of something, well, you're going to have 5of that something, minus 10. These two x's negate each other. And you're left with equals 15. Now we can get ridof this negative 10 by adding 10 to both sides. You know, I likethat green color when I do stuff to both sides. So I can add 10 to both sides. And I'm left with5x-- these negate each other-- is equal to 25. And this is the home stretch. You see where this is going. We can divide both sides by 5. And we are left withx is equal to 5. Now let's verify thatthis actually worked. So let's go back tothe original equation. We have 7 minus 10/5. This needs to beequal to-- I'm just taking our 5 andsubstituting it back here. This needs to beequal to 2 plus 15/5. So this is 7 minus 10/5. This is just 2. It needs to be equal to 2plus 15/5, which is just 3. So 2 plus 3, 7 minus2 is 5, 2 plus 3 is 5, 5 is indeed equal to 5. And we are done.
